Question

Mă puteți ajuta,vă rog frumos?

Answer 1

$\displaystyle \lim_{x \to -2} \frac{x^3+x^2-8x-12}{x^3-3x-10} = \frac{(-2)^3+(-2)^2-8 \cdot (-2)-12}{(-2)^3-3 \cdot (-2)-10} = \\ \\ = \frac{-8+4+16-12}{-8+6-10} = 0 \\ \\ \lim_{x \to -2} \frac{x^3+x^2-8x-12}{x^3-3x-10} =0$