Question

Ma puteti ajuta va rog frumos?

Answer 1

a) -6+3x=0/+6
3x=6/:3
x=2

b)-3x+3=0/-3
-3x=-3/: (-3)
x=1

c)-9x+18=0/-18
-9x=-18/: (-9)
x=2

d)5x-20=0/+20
5x=20/:5
x=4

e) √5x+√20=0/-√20

√5x=-√20/: √5
x=-√4= -2

f) √3x-√3=0/+ √3

√3x= √3/: √3
x=1

g) √2x-√18+2 √2=0

√2x-3 √2+2 √2=0

√2x+ √2=0/-√2

√2x=-√2/: √2
x=-1

h) (5-√7)-5+ √7=0
0=0

i) x √2-√3=0/+ √3
x √2= √3/: √2
x= √3/√2
x= √6/2

Answer 2

Răspuns:

a. - 6+3x=0

3x=6

x=2

Verificare: -6+3•2=0

-6+6=0

0=0

b. - 3x+3=0

-3x=-3 |:-3

x=1

Verificare: -3•1+3=0

- 3+3=0

0=0

c. - 9x+18=0

-9x=18 |:9

-x=2 |:-1

x=-2

Verificare: -9•-2+18=0

- 18+18=0

0=0

d.5x-20=0

5x=20

x=4

Verificare: 5•4-20=0

20-20=0

0=0

e.

$\sqrt{5} x + \sqrt{20} = 0 \\ \sqrt{5} x = - \sqrt{20} \\ x = - \sqrt{4}$

Verificare :

$\sqrt{5} \times - \sqrt{4} + \sqrt{20} = 0 \\ - \sqrt{20} + \sqrt{20} = 0 \\ 0 = 0$

f.

$\sqrt{3} x - \sqrt{3} = 0 \\ \sqrt{3} x = \sqrt{3} \\ x = \sqrt{3} \div \sqrt{3} \\ x = 1$

Verificare :

$\sqrt{3} \times 1 - \sqrt{3} = 0 \\ \sqrt{3} - \sqrt{3} = 0 \\ 0 = 0$

g.

$\sqrt{2} x - \sqrt{18} + 2 \sqrt{2} = 0 \\ \sqrt{2} x - 3 \sqrt{2} + 2 \sqrt{2 } = 0 \\ \sqrt{2} x - 1 \sqrt{2} = 0 \\ \sqrt{2} x = \sqrt{2} \\ \times = 1$

$\sqrt{2} \times 1 - \sqrt{18} + 2 \sqrt{2} = 0 \\ 1 \sqrt{2} - 3 \sqrt{2} + 2 \sqrt{2} = 0 \\ 0 = 0$

h.

$(5 - \sqrt{7} ) - 5 + \sqrt{7} = 0 \\ 5 - \sqrt{7 } - 5 + \sqrt{7} = 0 \\ 0 = 0$

Sper ca te am ajutat!!