Question

Ma puteți ajuta va rog la 20?

Answer 1

Răspuns:

Fie a,b,c,d cele patru numere cautate

$\it a+b+c+d=36,2\\\\\\c=\dfrac{a+b}{2}\\\\\\d=\dfrac{b+c}{2} \Rightarrow 2d=b+c\\\\\\d=a+\dfrac{a}{2}\Rightarrow d=\dfrac{2a+a}{2}\Rightarrow 2d=3a\\\\\\\Rightarrow b+c=3a\\\\\\inlocuim \: in\:suma\\\\\\ a+3a+\dfrac{2a+a}{2}=36,2\\\\\\\dfrac{2a+2\cdot3a+3a}{2}=36,2\\\\11a=36,2\cdot2\\\\11a=72,4 \Rightarrow a=72,4:11 \Rightarrow \boxed{\it a=6,6}\\\\\\ d = 6,6\cdot3:2\Rightarrow \boxed{\it d=9,9}$

$\it b+c = 3\cdot6,6\Rightarrow b+c=19,8\Rightarrow \boxed{\it c=19,8-b}\\\\\\c=\dfrac{a+b}{2}\Rightarrow \boxed{\it c=\dfrac{6,6+b}{2}}\\\\egalam\:ecuatiile\\\\19,8-b = \dfrac{6,6+b}{2}\\\\39,6 -2b=6,6+b\\\\39,6-6,6=b+2b\\\\33=3b\Rightarrow b=33:3\Rightarrow\boxed{\it b=11}\\\\c = 19,8-11\Rightarrow \boxed{\it c=8,8}\\\\\\Verificare: 6,6+11+8,8+9,9=36,3\:(adevarat)$

Answer 2

Răspuns:

Explicație pas cu pas: