Question

Mareste de opt ori fractia:2supra3,3supra4,4supra5,5supra6,9supra8

Answer 1

(8pe1- e 8 intreg)
inmultim numaratorii intre ei si numutorii intre ei)
2pe3×8pe1=(adica 2×8 si 3×1 )=16pe3
3pe4×8pe1=24pe4(simplificam la4)=6pe1
4pe5×8pe1=32pe5
5pe6×8pe1=40pe6(simplificam la2)= 20pe3
9pe8×8pe1=72pe8(simplificam la8)=9pe1

Answer 2

2
$2x5 {. {8 {?}^{2} }^{2} }^{2}$