Question

masa Carbonului, masa Hidrogenului si masa Oxigenului din 120g C2H4O2, 35g CH4, 80g C2H6O

Answer 1

Răspuns:

M(C₂H₄O₂) = 2A(C) + 4A(H) + 2A(O) = 2 × 12 + 4 × 1 + 2 × 16 = 60 g/mol

60g C₂H₄O₂.....24g C.....4g H.....32g O

120g C₂H₄O₂.....x g C.....y g H.....z g O

x = 120 × 24 : 60 = 48g C

y = 120 × 40 : 60 = 8g H

z = 120 × 32 : 60 = 64g O

M(CH₄) = A(C) + 4A(H) = 12 + 4 × 1 = 16 g/mol

16g CH₄.....12g C.....4g H

35g CH₄.....v g C.....w g H

v = 35 × 12 : 16 = 26,25g C

w = 35 × 4 : 16 = 8,75g H

M(C₂H₆O) = 2A(C) + 6A(H) + A(O) = 2 × 12 + 6 × 1 + 16 = 46 g/mol

46g C₂H₆O.....24g C.....6g H.....16g O

80g C₂H₆O.....a g C.....b g H.....c g O

a = 80 × 24 : 46 = 41,73g C

b = 80 × 6 : 46 = 10,43g H

c = 80 × 16 : 46 = 27,82g O

-Mihai