Question

Masa de azot care se afla intr-un volum de 4,48L amoniac este?

Answer 1

nr.moli= V/ V molar= 4,48/ 22,4=0,2moli NH3
nr.moli= masa/ masa molara⇒m= n*M
M NH3= 14+3=17g/mol
m=0,2*17=3,4 gNH3
In 17gNH3................14gN
    3,4gNH3..........     x   gN
x=3,4*14/ 17=2,8gN