Question

masa de clor care se afla in 10 kmol de MgCl2

Answer 1

$M_{MgCl_2}=24+(2*35,5)=24+71=95\ g/mol$
$10\ kmoli=10000\ moli$
[tex]1\ mol\ MgCl_2..........71\ g\ Cl_2 \\ 10\ kmoli\ MgCl_2...............x \\ \\ x=\frac{71\ g*10\ kmoli}{1\ mol}=710\ kg\ Cl_2[/tex]