Question

masa de potasiu continuta in 0,25 mol de clorura de potasiu ​

Answer 1

Răspuns:

Explicație:

0,25 moli KCl

g K

MKCl= 39 + 35,5= 74,5-------> 74,5g/moli

m= n .M

m= 0,25moli . 74,5g/moli=18,625 gKCl

74,5g KCl---------39 g K

18,625g-----------------x

x= 18,625 . 39 : 74,5=9,75 g K

n= 9,75g : 39g/moli = 0,25 moli K