Question

Masa de solutie de acid clorhidric de concentratie 20% ce se poate aditiona la 89,6L acetilena de puritate 90%

Answer 1

n=V/Vm= 89.6 l/ 22,4 l/mol= 4 mol acetilena impura
p=n,px100/n,i---> n,pur=90x4/100 mol= 3,6 mol acetilena pura

daca aditia este totala
1mol........2mol
CH≡ CH+ 2HCl---> CH2Cl-CH2Cl
3,6mol........x= 7,2mol HCl
m,HCl=nxM= 7,2x36,5 g=262,8 gHCl....aceasta masa este dizolvata in solutie-> md
c= mdx100/ms--->ms=262,8x100/20g=.........................calculeaza !!!!!