Question

masa geometrica la (2,8).
Masa geometrica la radical din3 și 3radical din 3
Masa aritmetica 3,4,5​

Answer 1

$\it m_{g} = \sqrt{a \cdot b} = \sqrt{2 \cdot 8} = \sqrt{16} = 4 \\ \\ m_{g} = \sqrt{a \cdot b}  = \sqrt{\sqrt{3} \cdot 3\sqrt{3} } = \sqrt{3 \cdot 3} = \sqrt{3^{2} } = 3 \\ \\ m_{a} = \frac{a~+~b~+~c}{3} = \frac{3 + 4 + 5}{3}  = \frac{12}{3} = 4$

Answer 2

Răspuns:

    a) $M_{g}=\sqrt{2*8}$

    $M_{g}=\sqrt{16}$

    $M_{g}=4$

    b) $M_{g}=\sqrt{\sqrt{3}*3\sqrt{3}}$

    $M_{g}=\sqrt{3*3}$

    $M_{g}=\sqrt{9}$

    $M_{g}=3$

    c) $M_{a}=\frac{3+4+5}{3}$

    $M_{a}=\frac{12}{3}$

    $M_{a}=4$

Formule aplicate:

    $M_{g}=\sqrt{a*b}$

    $M_{a}=\frac{x_1+x_2+x_3...+x_n}{n}$