Question

Matematica, exercițiul 1 repede va rogg

Answer 1

Răspuns:

0

Explicație pas cu pas:

f : R --> R ; f(x) = 2x-1

f[√(1/2)]·f[√(1/3)]·........·f[√(1/10)] = ?

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f[√(1/2)] = 2·√(1/2) - 1 = 2/√2 - 1 = 2√2 /2 - 1 = √2 - 1

f[√(1/3)] = 2·√(1/3) - 1 = 2√3 /3 - 1

f[√(1/4)] = 2·√(1/4) -1 = 2·1/2 - 1 = 1 - 1 = 0

=> produsul f[√(1/2)]·f[√(1/3)]·........·f[√(1/10)]  = 0

Answer 2

$\it f\Big(\sqrt{\dfrac{1}{4}}\Big)=f\Big(\dfrac{1}{2}\Big)=2\cdot\dfrac{1}{2}-1=1-1=0 \Rightarrow\ produsul\ dat\ este \ \ 0.$