Question

matematică test!!!..​

Answer 1

$a = \sqrt{ \frac{1}{4} } + \sqrt{ \frac{1}{9} } + \sqrt{ \frac{1}{36} } = \frac{1}{2} + \frac{1}{3} + \frac{1}{6} = \frac{3}{6} + \frac{2}{6} + \frac{1}{6} = \frac{3 + 2 + 1}{6} = \frac{6}{6} = 1$

$a = |3 - \sqrt{5} | + | \sqrt{5} + \sqrt{3} | + | \sqrt{3} - 2| = 3 - \sqrt{5} + \sqrt{5} + \sqrt{3} - \sqrt{3} + 2 = 3 + 2 = 5$

${(a - 7)}^{6} = {(5 - 7)}^{6} ={( - 2)}^{6} =64$