Question

Media arimetrica a nr. a,b,c:

a=3✔20-✔48

b=✔108-3✔8

c=✔72-✔12


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Answer 1

a = 3√20 - √48

= 3√2²×5 - √3×4²

= 6√5 - 4√3

b = √108 - 3√8

= √3×6² - 3√2³

= 6√3 - 6√2

c = √72 - √12

= √2×6² - √3×2²

= 6√2 - 2√3

Ma = (a + b + c)/3

= (6√5 - 4√3 + 6√3 - 6√2 + 6√2 - 2√3)/3

= 6√5/3

= 2√5