Question

media arimetrica a trei numereeste egalacu 16.Aflati umerele stind ca ele sunt direct proportionale cu! numerele 4, 5 ,7.

Answer 1

ma=16
a/4=b/5=c/7
a/4=b/5      a=4b/5
b/5=c/7      c=7b/5
a+b+c=4b/5+b+7b/5=11b/5+5b/5=16b/5
ma=(a+b+c)/3
16=16b/5:3
16=16b/5*1/3
16=16b/15
16b=16*15
b=15
a=4b/5=4*15/5=12
a=12
c=7b/5=7*15/5=21
c=21
proba 21+12+15=48:3=16= ma