Question

Media aritmetica a 3 nr.este 100.doua dintre ele sunt 83 si 112.determinat i al treilea număr

Answer 1

(83+112+n):3=100
83+112+n=100x3
195+n=300
n=300-195
n=105
V: (83+112+105):3=300:3=100

Answer 2

83+112+a=100×3 ;83+113+a=300; a=300-83-112 ; a=105 ; 105+83+112÷3=300÷3=100