Question

media aritmetica:a=5,5 ,b=1,8(3)​

Answer 1

$m_{a}(a.b) = \frac{a + b}{2} = \frac{5.5 + 1.8(3)}{2} =$

$= \frac{ \frac{55}{10} + 1 \frac{83 - 3}{90} }{2} =$

$= \frac{ \frac{11}{2} + 1 \frac{80}{90} }{2} =$

$= \frac{ \frac{11}{2} + 1 \frac{8}{9} }{2} =$

$= \frac{ \frac{11}{2} + \frac{17}{9} }{2} =$

$= \frac{ \frac{99}{18} + \frac{34}{18} }{2} =$

$= \frac{ \frac{133}{18} }{2} =$

$= \frac{133}{36}$

Answer 2

Răspuns:

    $m_{a}=\frac{11}{3}$

Explicație pas cu pas:

    ✿ Salut! ✿

✎ Cerință: Calculați media aritmetică.

    $m_{a}=\frac{a_{1}+a_{2}+...+a_{n}}{n}$

    $m_{a}=\frac{5,5+1,8(3)}{2}$

    $1,8(3)=1\frac{83-8}{90}=1\frac{75}{90}=\frac{1*90+75}{90}=\frac{165}{90}=\frac{55}{30}$

    $m_{a}=\frac{^{3)}\frac{55}{10}+\frac{55}{30}}{2}$

    $m_{a}=\frac{\frac{165}{30}+\frac{55}{30}}{2}$

    $m_{a}=\frac{\frac{2\not20}{\not30}}{2}$

    $m_{a}=\frac{\frac{22}{3}}{2}$

    $m_{a}=\frac{22}{3}:2$

    $m_{a}=\frac{\not22}{3}*\frac{1}{\not2}$

    $m_{a}=\frac{11}{3}$