Question

media aritmetica a lui a,b,c este 70 si au simultan loc relatiile 2a=3b 10b=4c

Answer 1

(a+b+c)/3 = 70 =>a+b+c=210
2a=3b=k
a=k/2
b=k/3

10b=4c=k'
b=k'/10
c=k'/4

k/3 = k'/10 =>k'=10k/3
=>c=10k/12=5k/6

k/2 + k/3 + 5k/6 = 210
Numitor comun 12
6k+4k+10k=210•12
20k=210•12
k=126
a=126/2=63
b=126/3=42
c=(5×126)/6=5×21=105

Answer 2

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