Question

media aritmetica a nr 1/4; 10/3; 2intregi si4/9

Answer 1

$m_{a} = \frac{ \frac{1}{4} + \frac{10}{3} + 2 \frac{4}{9} }{3}$

$m_{a} = \frac{ \frac{1}{4} + \frac{10}{3} + \frac{2 \times 9 + 4}{9} }{3}$

$m_{a} = \frac{ \frac{1}{4} + \frac{10}{3} + \frac{22}{9} }{3}$

$m_{a} = \frac{ \frac{9}{36} + \frac{120}{36} + \frac{88}{36} }{3}$

$m_{a} = \frac{ \frac{9 + 120 + 88}{36} }{3}$

$m_{a} = \frac{ \frac{217}{36} }{3}$

$m_{a} = \frac{217}{36} \times \frac{1}{3}$

$m_{a} = \frac{217}{108}$