Question

media aritmetica a numerelor 1 pe 3, 0,25 si 1 pe 12 este egala cu

Answer 1

$M _{a} =\frac{ \frac{1}{3}+0,25+ \frac{1}{12} }{2}$
$M _{a} =\frac{ \frac{1}{3}+ \frac{25}{100} + \frac{1}{12} }{2}$
$M _{a} =\frac{ \frac{1}{3}+ \frac{1}{4} + \frac{1}{12} }{2}$
$M _{a} =\frac{\frac{2}{3}}{2}$
$M _{a} = \frac{2}{3} : \frac{2}{1} = \frac{2}{3} * \frac{1}{2} = \frac{2}{6} ^{(2} = \frac{1}{3} ;$