Question

Media aritmetica a numerelor 2.2(3) ; 3,7(4) ; 1,0(2) este:

A:1, 99
B:2
C:5 supra 3
D:6


dau coroana, dacă imi explicati​

Answer 1

Ma = (a+b+c)/ 3.

Ma = (2,2(3) + 2,7(4) + 1,0(2)) /3

Ma = ( 77/30 + 136 /45 + 11 / 90 ) / 3

Ma = 1,99

scuze

raspunsul e a