Question

media aritmetica a numerelor 2,(3); 3supra 5 ; 0,1(3)=

Answer 1

2,(3)=2  3/9 =21/9
3/5
0,1(3)=13/90

Ma=(21/9 + 3/5 + 13/90)/3=

21/9 + 3/5 + 13/90  stabilim numitorul comun ca fiind 450, atunci:
(50*21 + 3*90 + 13*5)/450=1050+270+65)/450=1385/450=277/90

Ma = 277/90 : 1/3 = 277/90 * 3 = 277*3/90=277/30