Question

media aritmetica a numerelor a=13-4radical din 3 si b=(2 radical din 3 + 1)^2 este....?​

Answer 1

$\it a=13-4\sqrt3\\ \\ b=(2\sqrt3+1)^2=(2\sqrt3)^2+2\cdot2\sqrt3\cdot1+1^2=12+4\sqrt3+1=13+4\sqrt3\\ \\ \\ m_a=\dfrac{a+b}{2}=\dfrac{13-4\sqrt3+13+4\sqrt3}{2}=\dfrac{26}{2}=13$