Question

media aritmetica a numerelor a= 8-$8- \sqrt[3]{7}+ \frac{1}{2}(3+ \sqrt{7}) la putera 2$ b= 24

Answer 1

[tex]b=24 \\ M_{a} \frac{24+1,00000005}{2} \\ M_{a} =12,5[/tex][tex]8- \sqrt[3]{7} + \frac{1}{2} (3+ \sqrt{7} ) ^{2} = \\ =8- \sqrt[3]{7} + \frac{1}{2} *5,64575131 ^{2} \\ =8-7,93725393+ \frac{1}{2} *31,8745079 \\ =8-7,93725393+ \frac{31,8745079}{2} \\ =0,06274607+ \frac{31,8745079}{2} \\ = \frac{2,0000001}{2} \\ =1,00000005[/tex]