Question

media aritmetica a numerelor a si b
a= radical din 12 + radical din trei si b=15 supra radical din trei

Answer 1

a=√12+√3
a=2√3+√3
a=3√3
b=15:√3 (rationalizezi)
b=15√3:3
b=5√3
ma=(a+b):2
ma=(3√3+5√3):2
ma=8√3:2
ma=4√3

Answer 2

$\displaystyle a= \sqrt{12} + \sqrt{3} =2 \sqrt{3} + \sqrt{3} =3 \sqrt{3} \\ \\ b= \frac{15}{ \sqrt{3} }= \frac{15 \sqrt{3} }{3} =5 \sqrt{3} \\ \\ m_a= \frac{a+b}{2} = \frac{3 \sqrt{3} +5 \sqrt{3} }{2} = \frac{8 \sqrt{3} }{2} =4 \sqrt{3}$