Question

media aritmetica a trei nr impare consecutive este 47.aflati numerele

Answer 1

[(2a+1)+(2a+3)+2a+5)]/3=47
6a+9=141
6a=132
a=22
2a+1=2*22+1=45
2a+3=2*22+3=47
2a+5=2*22+5=49

Answer 2

(a+b+c):3= 47
b= a+2
c= a+4
(a+a+2+a+4):3= 47
(3a+6)= 47×3
3a+6= 141
3a= 135
a= 135:3
a= 45
b= 45+2 => b= 47
c= 45+4 => c= 49
Proba:
(45+47+49):3= 47
141:3= 47
47= 47