Question

Media aritmetica a trei numere consecutive est 402.Aflaţi numerele

Answer 1

notam numerele cu x, y si z;
x-nr cel mai mic
y=x+1
z=x+2
ma(x+y+z):2=402
x+y+z=402:2
x+y+z=201
x+x+1+x+2=201
3x+3=201
3x=201-3
3x=198
x=198:3
x=66