Question

Media aritmetica a trei numere este 4,46. Aflați numerele dacă media primelor doua este 3,69, iar a ultimelor două este 5,56.

Answer 1

a+b+c/3=4,46
a+b/2=3,69
b+c/2=5,56
3,69+c/3=4,46
c=3,23
b+c/2=5,56
Apoi inlocuiesti pe c
3,23/2=5,56-b
b=5,56-1,61
b=3,95
a+b+c/3=4,46
a+3,95+3,23/3=4,46
a+2,39=4,46|-2,39
a=2,07

Answer 2

(x+y+z):3=4,46=>x+y+z=4,46×3=13,38

(x+y):2=3,69=>x+y=2×3,69=7,38

(y+z):2=5,56 =>y+z=5,56×2=11,12

z=13,38-7,38=6
x=13,38-11,12=2,26
y=13,38-(x+z)=13,38-8,26=5,12