Question

Media aritmetica a trei numere naturale consecutive este 186.
Determinati numerele

Answer 1

$\frac{a+(a+1)+(a+2)}{3} =186 \\ a+a+1+a+2=186*3 \\ 3a+3=558 \\ 3a=558-3 \\ a=555:3 \\ a=185 \\ 185+1=186 \\ 185+2=187 \\ nr.sunt.185,186,187$

Answer 2

[tex]Numerele~consecutive~sunt:a,a+1,a+2 \\ \frac{a+a+1+a+2}{3}=186(inmultim~pe~diagonala) \\ a+a+1+a+2=186*3 \\ a+a+1+a+2=558 \\ 3a+3=558 \\ 3a=558-3 \\ 3a=555 \\ a=555:3 \\ a=185 (primul~numar) \\ a+1=185+1=186(al~doilea~numar) \\ a+2=185+2=187(al~treilea~numar) [/tex]