Question

Media aritmetica a trei numere naturale este 123. aflati suma numerelor.

Answer 1

$fara.nr.consecutive-\frac{a+a+a}{3} =123=\ \textgreater \ 3a=369=\ \textgreater \ a=123 \\ cu.nr.consecutive- \frac{a+a+1+a+2}{3} =123=\ \textgreater \ 3a+3=123=\ \textgreater \ 3a=120 \\ a=40,b=41,c=42$

Answer 2

Ma=a+b+c/3=123
a+b+c=123×3
a+b+c=369