Question

Media gemetrica a numerelor 2 radical din 3 si 24 radical din 3

Answer 1

$m_{g} = \sqrt{2 \sqrt{3} \times 24 \sqrt{3} }$

$m_{g} = \sqrt{2 \times 24 \sqrt{3 \times 3} }$

$m_{g} = \sqrt{48 \sqrt{9} }$

$m_{g} = \sqrt{48 \times 3}$

$m_{g} = \sqrt{144}$

$m_{g} = 12$

Answer 2

Ma=√(2√3·24√3)=√(48·3)=√144=12