Question

Media geometrica a=7radical din 8 - radical din 50, b=3 radical din 24 - radical din 96

Answer 1

Răspuns:

$\mathbf{Mg = 6 \sqrt[4]{3} }$

Explicatie pas cu pas:

$\boxed{\mathbf{ Mg = \sqrt{a \times b} }}$

$\mathbf{a = 7 \sqrt{8} - \sqrt{50} = 14 \sqrt{2} - 5 \sqrt{2} = 9 \sqrt{2} }$

$\mathbf{ b = 3 \sqrt{24} - \sqrt{96} = 6 \sqrt{6} - 4 \sqrt{6} = 2 \sqrt{6} }$

$\mathbf{Mg = \sqrt{9 \sqrt{2} \times 2 \sqrt{6} } = \sqrt{18 \sqrt{12} } }$

$\mathbf{Mg = \sqrt{36 \sqrt{3} } = 6 \sqrt{ \sqrt{3} } }$

$\mathbf{Mg = 6 \sqrt[2 \times 2]{3} = \boxed{\mathbf{6 \sqrt[4]{3} }} }$

Bafta!