Question

media geometrica a lui √12+√27 si √3+√48​

Answer 1

$\sqrt{12} + \sqrt{27} = 2 \sqrt{3} + 3 \sqrt{3} = 5 \sqrt{3}$

$\sqrt{3} + \sqrt{48} = \sqrt{3} + 4 \sqrt{3} = 5 \sqrt{3}$

media geometrică:

$\sqrt{5 \sqrt{3} \times 5 \sqrt{3} } = \sqrt{25 \times 3} = \sqrt{75} =5 \sqrt{3}$