Question

Media geometrica a nr. 4- radical din 3 si 4+ radical din 3

Answer 1

$m_g= \sqrt{a\cdot b} \\\\\\ m_g= \sqrt{(4-\sqrt{3})*(4+\sqrt{3})} \\\\ m_g= \sqrt{16-3} \\\\ \boxed{m_g=\sqrt{13}}$