Question

Media geometrica a nr x= radical 288 si y=radical 162

Answer 1

[tex]m_g= \sqrt{ \sqrt{288}* \sqrt{162} } \\\\ m_g= \sqrt{46656} \\ m_g=216[/tex]

Answer 2

[tex]\it a= \sqrt{288}=\sqrt{144\cdot2} = 12\sqrt2 \\\;\\ b=\sqrt{162} =\sqrt{81\cdot2} = 9\sqrt2[/tex]

$\it m_g=\sqrt{a\cdot b} = \sqrt{12\sqrt2\cdot9\sqrt2} =\sqrt{12\cdot9\cdot 2} =\sqrt{4\cdot3\cdot9\cdot2} = 6\sqrt6$