Question

Media geometrica a numerelor: 16 si 81, 144 si 100, 121 si 4, 225 si 169. Atat. Multumesc!

Answer 1

$\boxed{\bold{M_g= \sqrt{a*b} }} \\ \\M_g= \sqrt{16*81}= \sqrt{4*9} = 36\\\\M_g= \sqrt{144*100}= \sqrt{12*10}=120\\\\M_g= \sqrt{121*4}= \sqrt{11*2}=22\\\\M_g= \sqrt{225*169}= \sqrt{15*13}=195$