Question

media geometrica a numerelor a= 2(radical din )3 b=6(radical)3

Answer 1

[tex]mg= \sqrt{a*b} \\ mg= \sqrt{2 \sqrt{3}*6 \sqrt{3} } \\ mg= \sqrt{12*3} mg= \sqrt{36}=6 [/tex]

Answer 2

$M.g.= \sqrt{a\cdot b} \\\\M.g.= \sqrt{2 \sqrt{3}\cdot6 \sqrt{3} } \\\\M.g.= \sqrt{12\cdot3}\\\\\boxed{M.g.=6 }$