Question

media geometrica a numerelor a=|2 radical din 7 - 8| si b=| 2 radical din 7 + 8|

Answer 1

$\sqrt{28} \ \textless \ \sqrt{64} =\ \textgreater \ |2 \sqrt{7} -8| \ \textless \ 0 =\ \textgreater \ |2 \sqrt{7} -8|=8- 2\sqrt{7}$

$|2 \sqrt{7} +8| \ \textgreater \ 0 =\ \textgreater \ |2 \sqrt{7} +8 | = 2 \sqrt{7}+8$

$mg= \sqrt{a*b}= \sqrt{(8- 2 \sqrt{7})(8+2 \sqrt{7}) }= \sqrt{64-28} = \sqrt{36} =6$