Question

media geometrica a numerelor a=|radical 15-4|+|3-radical 15| si b=|2radical2-3|+|1-2radical2|

Answer 1

$a = | \sqrt{15} - 4| + |3 - \sqrt{15} | \\ = 4 - \sqrt{15} + \sqrt{15} - 3 \\ = 1$
$b = |2 \sqrt{2} - 3 | + |1 - 2 \sqrt{2} | \\ = 3 - 2 \sqrt{2} + 2 \sqrt{2} - 1 \\ = 2$
$mg = \sqrt{ab} = \sqrt{1 \times 2} = \sqrt{2}$