Question

Media geometrica a numerelor: a=radical din 216 si b=radical din 54

Answer 1

media geometrica =√axb(1)
deci a=√216
b=√54
inlocuim in formula(1) √√216x√54=√11664=108

Answer 2

$a= \sqrt{216} =6 \sqrt{6} \\ b= \sqrt{54} =3 \sqrt{6} \\ m_g= \sqrt{a \cdot b} = \sqrt{6 \sqrt{6} \cdot 3 \sqrt{6} } = \sqrt{18 \cdot 6} = \sqrt{108} =6 \sqrt{3}$