Question

media geometrica a numerelor radical din 27 si radical din 48

Answer 1

$\sqrt{27}=3 \sqrt{3} \\ \sqrt{48}= 4 \sqrt{3} \\ M_g= \sqrt{3 \sqrt{3} \cdot 4 \sqrt{3} }= \sqrt{12\cdot3}= \sqrt{36}=6$