Question

Media geometrica a radicalilor din 288 si 162(scrieti rezolvarea)

Answer 1

$288=12 \sqrt{2}$
$\sqrt{162} =9 \sqrt{2}$
$Mg= \sqrt{ \sqrt{288} * \sqrt{162} } -> Mg= \sqrt{ 12\sqrt{2} * 9 \sqrt{2} } -> Mg= \sqrt{108 * 2} -> Mg= \sqrt{216} -> Mg=6 \sqrt{6} .$.