Question

Media geometrica ale lui a si b 
a) a=3supra2 si b= 2 supra 3
b)a=radical din 10 -3(-3 nu e in radical)
b= radical din 10 +3

Answer 1

$mg (a, b) = \sqrt{a*b} \\ \\ a) \\ mg= \sqrt{\frac{3}{2}*\frac{2}{3}} = \sqrt{\frac{3*2}{2*3}} = \sqrt{\frac{6}{6}}= \sqrt{1}=1 \\ \\ \\ b) \\ mg = \sqrt{(\sqrt{10}-3 )(\sqrt{10}+3)} =\sqrt{(10-9 )}= \sqrt{1} = 1$