Question

mere ,pere ,caise, nuci; 2/5 din nr. fructelor=mere, perele=1/2 din rest, caisele=1/3 din noul rest si sunt 10 nuci; Cate fructe erau?

Answer 1

2/5 ·y=2y/5=m;
a ramas y-2y/5=5y/5-2y/5=3y/5;
⇒1/2·3y/5=3y/10=p;
a ramas  3y/5-3y/10=6y/10-3y/10=3y/10;
⇒1/3·3y/10=1/1·y/10=y/10=c;
a ramas 3y/10-y/10=2y/10=y/5;
⇒y/5=10
⇒y=5·10
⇒y=50[fructe erau];