METODA MERSULUI INVERS
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a)
(x+20):12+68=78
(x+20):12=78-68
(x+20):12=10
x+20=12x10
x+20=120
x=120-20
x=100
b)
(x+282-75):2=104
(x+282-75)=2x104
x+282-75=208
x+207=208
x=208-207
x=1
c)
X x 4:10+101=133
Xx4:10=133-101
Xx4:10=32
Xx4=10x32
Xx4=320
X=320:4
X=80
d)
101×[101-(101-102:x)]=202
101-(101-102:x)=202:101=2
101-2=(101-102:x)
99=101-102:x
101-99=102:x
2=102:x
x=102:2
x=51
e)
369 - [(x+112):5+113] = 434
369-434= [(x+112):5+113]
- 65 = (x+112):5+113
-65-113=(x+112):5
-178=(x+112):5
(x+112)=5 x (-178)= - 890
x+112= - 890
x= - 890-112
x= -1002
f)
104:[(x-3×8)×2:7]=13
104:13=(x-3×8)×2:7
8=(x-3×8)×2:7
8x7=(x-3×8)×2
56=(x-3×8)×2
56:2=x-3×8
28=x-24
x=28+24
x=52
(x+20):12+68=78
(x+20):12=78-68
(x+20):12=10
x+20=12x10
x+20=120
x=120-20
x=100
b)
(x+282-75):2=104
(x+282-75)=2x104
x+282-75=208
x+207=208
x=208-207
x=1
c)
X x 4:10+101=133
Xx4:10=133-101
Xx4:10=32
Xx4=10x32
Xx4=320
X=320:4
X=80
d)
101×[101-(101-102:x)]=202
101-(101-102:x)=202:101=2
101-2=(101-102:x)
99=101-102:x
101-99=102:x
2=102:x
x=102:2
x=51
e)
369 - [(x+112):5+113] = 434
369-434= [(x+112):5+113]
- 65 = (x+112):5+113
-65-113=(x+112):5
-178=(x+112):5
(x+112)=5 x (-178)= - 890
x+112= - 890
x= - 890-112
x= -1002
f)
104:[(x-3×8)×2:7]=13
104:13=(x-3×8)×2:7
8=(x-3×8)×2:7
8x7=(x-3×8)×2
56=(x-3×8)×2
56:2=x-3×8
28=x-24
x=28+24
x=52
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