Question

Metoda mersului invers clasa a IV-a. 49 de puncte !!!

20xe-(1950+550):100=6175
35xf+(800-752:4):2=551
g:2+(100-1632:51)x2=286
244-hx5+(300-6x16):4=255

Answer 1

20 x e - 2500 : 100 = 6175
20xe  - 25 = 6175
20xe = 6175 +25 
20 x e = 6200
e = 6200:20
 e = 310 

35 x f + ( 800  - 188) :2 = 551
35 x f +612 :2 = 551
35xf +306 = 551
35 x f = 551 - 306 
35 x f = 245 
f =245:35 
f= 7

g:2 +( 100 - 32 ) x 2 = 886 
g:2 +68 x2 =286 
g:2 + 136 = 286
g:2 = 286 - 136
g:2 = 150
g=150:2
g=75

244 - hx5 + ( 300 - 96) :4 = 255
244 -hx5 + 204 :4 =255
244 - hx5 +51 = 255
244 -hx5 = 255-51
244- hx5 = 204
hx5 = 244-204
hx5 = 40 
h=40:5
 h=8