Question

metpda grafica suma a patru nr consecutive pare. este 52.Afla nr

Answer 1

a+a+2+a+4+a+6=52
4a+12=52
4a=52-12
4a=40
a=40:4
a=10
b=10+2
b=12
c=10+4
c=14
d=10+6
d=16
proba: 10+12+14+16=22+14+16=36+16=52

Answer 2

a+b+c+d=52
a,b,c,d=numere.pare.consecutive
a,b,c,d=?
a=1segment
b=1segment+2
c=1segment+2+2
d=1segment+2+2+2
52-12=40(4segmente.egale)
40:4=10(a)
10+2=12(b)
10+2+2=14(c)
10+2+2+2=16(d)
Verificare:10+12+14+16=52
Sper ca te-am ajutat!