Question

mihai are 78 lei,george are 56 lei,teodor are 46 lei . Tata le imparte suma de 132 lei iar cei trei frati au acum sume egale de bani . Cati lei a dat tatal fiecarui baiat ?

Answer 1

Dupa ce le imparte banii au asa :
stim ca tatal le-a dat 132 deci $a+b+c=132$
$78+a=x$ Mihai
$56+b=x$ George
$46+c=x$ Teodor
$------------ adunare$
$78+56+46+a+b+c=x+x+x$
$180+a+b+c=3x$
$180+132=3x$
$3x=312$
$x=104$
$78+a=104=>a=104-78=26$ bani primiti de Mihai
$56+b=104=>b=104-56=48$ bani primiti de George
$46+c=104=>c=104-46=58$ bani primiti de Teodor

Answer 2

132 lei : 3 = 44 lei mihai: 78 + 44 = 122 george: 56 + 44 = teodor: 46 + 44 = 90