Question

modul de 1 plus radical din 2 +modul de radical din 2 minus2

Answer 1

 [tex]|\underbrace{1+\sqrt2}_{\ \textgreater \ 0}|+|\underbrace{\sqrt2-2}_{\ \textless \ 0}|=\\ =+(1+\sqrt2)-(\sqrt2+2)=\\ =1+\sqrt{\not2}-\sqrt{\not2}-2=-1[/tex]

Answer 2

$|1+ \sqrt{2} |+| \sqrt{2} -2|= \sqrt{2} +1+2- \sqrt{2} =1+2=3$