Question

modul de xpatrat+3x-4=0

Answer 1

I x² + 3x - 4 I = 0 
daca        x² +3x - 4 = 0
Δ =9 + 16 =25 
x₁ = ( - 3 - 5) /2 = - 4 
x₂ = ( -3 +5) /2 = 1
S = { -4 ; 1}

Answer 2

$\displaystyle |x^2+3x-4|=0 \\ x^2+3x-4=0 \\ a=1,b=3,c=-4 \\ \Delta=b^2-4ac=3^2-4 \cdot 1 \cdot (-4)=9+16=25\ \textgreater \ 0 \\ x_1= \frac{-3+ \sqrt{25} }{2 \cdot 1} = \frac{-3+5}{2} = \frac{2}{2} =1 \\ \\ x_2= \frac{-3- \sqrt{25} }{2 \cdot 1} = \frac{-3-5}{2} = \frac{-8}{2} =-4 \\ \\ S=\{-4;1\}$