Question

modul din x supra 2 +3x supra 4-5x supra 6 =15supra2

Answer 1

$\frac{1}{12} \times (6 \times |x| + 3 \times 3x - 12 \times \frac{5x}{6} \times \frac{15}{2} ) \\ \frac{1}{12} \times (6 \times |x| + 3 - \times 3x - 2 \times 5x \times \frac{15}{2} ) \\ \frac{1}{12} \times (6 \times |x| + 9x - 5x \times 15) \\ \frac{1}{12} \times (6 \times |x| + 9x - 75x) \\ \frac{1}{12} \times (6 \times |x| - 66x) \\ \frac{1}{12} \times 6( |x| - 11x) \\ \frac{1}{2} \times |x| - 11x)$